FiveTech Support Forums

It is not a bug. It is the expected behavior.

AFill( aArray, {} ) results in filling all elements of aArray with reference to the pointer of the same array {}

Let us see this example:

x := y := {} // both x and y contain the pointer to the same array.
So whether we use the variable x or y, we are operating on the same array.

AAdd( x, 1 ) // this is same as AAdd( y, 1 ) because x and y hold reference to the same array.
Now x[ 1 ] contains 1 and y[ 1 ] also contains 1

AFill( aArray, Array(0) ) is the recommended way. Each element is assigned with pointer to a different array.

Thanks much! Is now clear.