Hi all,
My PC has Windows 7 32bit with 4 Gb/RAM
In my old version of FWH (8.10) the function nExtMem() gives 2147483647 (2GB)
In my new version of FWH (16.01 build 2) the same function nExtMem() gives 3219574784 (2,998... gb)
Is there any logic relation between them ?
I need to know it because i implemented a protection of my sw on hardware customer pc (memory,HD,CPU,...) and when i upgrade my the software on customer pc, i must be sure that is the same PC.
Any help ?
Tks
Romeo
On computers with more than 4 GB of memory, the GlobalMemoryStatus function can return incorrect information, reporting a value of –1 to indicate an overflow. For this reason, applications should use the GlobalMemoryStatusEx function instead.
#include "FiveWin.ch"
function Main()
LOCAL cMemoria, nBytes, nKBytes, nMBytes, nGBytes
nBytes := nExtMem()
nKBytes := nBytes / 1014
nMBytes := nKBytes / 1024
nGBytes := nMBytes / 1014
// Com erro - With Error
// aAdd( ::aTexto,"Memória: " + cValToChar( Int( nExtMem() / ( 1024 * 1024 ) ) + 1 ) + " MBs" )
// ? ( "Memóry Error: " + cValToChar( Int( nExtMem() / ( 1024 * 1024 ) ) + 1 ) + " MBs" )
? cMemoria := Trans( nExtMem(), "@E 9,999,999,999 Bytes free" )
? cMemoria := Trans( ( nExtMem() / ( 1024 * 1024 * 1014 ) ), "@E 999.99 GB Free" )
// or .97 = 4 Gbs.
? cMemoria := Trans( ( nExtMem() / ( 1024 * 1024 * 1014 ) + 1 ), "@E 999.99 GB Total" )
RETURN NIL
// END OF PROGRAMUnderstood the new function works well, BUT this not resolved my problem ! 
I will be not not able to detect the old RAM detected.
And i cannot sum 1 gb, as suggested, to the total RAM, because if a custmer has just 2 GB of real RAM i will get more than 2 GB of calculate RAM.
Thanks any
HB_FUNC( NEXTMEMOLD )
{
MEMORYSTATUS mst;
memset( &mst, 0, sizeof( MEMORYSTATUS ) );
mst.dwLength = sizeof( MEMORYSTATUS );
GlobalMemoryStatus( &mst );
hb_retnl( mst.dwTotalPhys );
}This can resolve my problem.
I'll try
Tks
R